如何对 0，0，0，0 进行运算得到 24？

比较普通难看一点的

$(\left(0!+0!\right)^{(0!+0!)})!=24$

$(\cos0\ or\sec0 +\cos0\ or\sec0+\cos0\ or\sec0+\cos0\ or\sec0)!=24$

$(0!+0!+0!+0!)!=24$

$[E(0!)+E(0!)+E(0!)+E(0!)]!=24, E(k)为第二类完全椭圆积分$

$[\lfloor E(0) \rfloor+\lfloor E(0) \rfloor+\lfloor E(0) \rfloor+\lfloor E(0) \rfloor]!=24$

$[\lfloor K(0) \rfloor+\lfloor K(0) \rfloor+\lfloor K(0) \rfloor+\lfloor K(0) \rfloor]!=24, K(k)为第一类完全椭圆积分$

$[\exp(0)+\exp(0)+\exp(0)+\exp(0)]!=24$

$(B_0 \ or \ C_0 +B_0 \ or \ C_0+B_0 \ or \ C_0+B_0 \ or \ C_0)!=24, B_n为Bernoulli数, C_n为Catalan数$

$[{\rm Ber}(0)+{\rm Ber}(0)+{\rm Ber}(0)+{\rm Ber}(0)]!=24, {\rm Ber}(x)为Kelvin\ Ber函数$

$-\tau(0!+0!)+0+0=24, \tau(x)为Ramanujan\ \tau函数$

用了阶乘但是看起来逼格还挺高的

$\lfloor\mathbf {L}_{0!}(\lceil \Gamma({\rm Hi}(0)))\rfloor!+0+0=24, \mathbf {L}_{\alpha}(z)为变形Struve函数, {\rm Hi}(z)为Scorers \ Hi函数$

$\lfloor{\rm Ei}(\lceil\frac{G(\arccos(C_0(0)))}{C_0(0)}\rceil)\rfloor!=24, G(z)为Goodwin-Staton积分, C_v(z)为Young函数, {\rm Ei}(x)为指数积分$

指正下面

的回答（定积分的位置错了应该在最外圈，下面所有积分的常数项均为0）：

$\frac{0!}{\int_0^{0!}\int\int\int 0! \ dx\ dx\ dx\ dx}=24$

又由于 $\int 1\ dx$ 可以简写为 $\int dx$ （至少我的那本AP Calculus AB教程上写着可以）于是我还能

$\lceil \int_0^{\exp(E(0))} \int \int \int \ dx\ dx\ dx\ dx\rceil+\int_0^{0!} dx=24$

不用阶乘的

$\lceil \Gamma^{(4)}(\cos or \sec 0)\rceil+0+0+0=24, \Gamma(n)为Euler第二类积分$

$\lfloor-\Gamma^{(7)}(\cos or \sec 0+\cos or \sec0)\rfloor+\lfloor -\Gamma'''(\cos or \sec0)\rfloor+\lfloor-\Gamma'''(\cos or \sec0)\rfloor=24$

$\lfloor-\psi^{(4)}(\cos or \sec 0+0+0+0)\rfloor=24, \psi^{(n)}为Digamma函数导数而非PolyGamma函数$

$\lceil {\rm erfi}'(\cos or \sec 0)\rceil \cdot \lfloor {\rm erfi}''(\cos or \sec 0)\rfloor +0+0=24, {\rm erfi}(z)为虚误差函数$

$\lfloor\exp( {\rm{Shi}} (\lceil-{\rm{si}} (0)\rceil))\rfloor\cdot\lceil-{\rm{si}} (0)\rceil+0+0=24, {\rm{Shi}}(x)为双曲正弦积分, {\rm si}(x)为x=\infty时为0的正弦积分$

$\lceil\mathbf {L}_{\cos 0}(\lceil \Gamma({\rm Gi}(0))\rceil)\rceil+0+0=24, {\rm Gi}(z)为Scorers \ Gi函数$

$\lceil cFh(\psi'(\lceil cFh(0) \rceil)) \rceil\cdot \lceil{\rm Im }(arccFh(0))\rceil \cdot {\rm erfc}(Y_0(0))=24, cFh(x)为Fibonacci双曲余弦函数, Y_\alpha(x)为第二类Bessel函数$

如果连三角都不要的话……

$\lceil\exp[A(0, A(0, 0))]\rceil\cdot\lceil \exp(\lfloor E(0)\rfloor)\rceil=24, A(a,b)为Ackermann函数$

$\lfloor-\Gamma(\zeta(0))\rfloor\cdot\lceil\Gamma(-\zeta(0))\rceil\cdot\lceil\Gamma(-\zeta(0))\rceil\cdot\lceil\Gamma(-\zeta(0))\rceil=24, \zeta(s)为Riemann\ \zeta函数$

$\lceil \frac{C(\xi(0))}{S(\xi(0))}\rceil \cdot \lceil \exp(\exp(0))\rceil+0=24, C(x)和S(x)为Fresnel积分, \xi(s)为Riemman\ \xi函数$

$\Gamma(\lfloor \exp(\exp(F(\lfloor \Pi(0|0)\rfloor)))\rfloor)+0+0=24, F(z)为Dawson积分, \Pi(n|k)为第三类完全椭圆积分$

$\lfloor{\rm Bi}(\lceil-\psi(\eta(0))\rceil)\rfloor \cdot \lceil K(0)\rceil \cdot \lceil K(0)\rceil \cdot \lceil K(0)\rceil=24, \eta(s)为Dirichlet\ \eta函数, {\rm Bi}(x)为Airy \ {\rm Bi}函数, K(n)为第一类椭圆积分$

$\lceil w\left(\sqrt{-{\rm erfc}(0)}\right) \rceil\cdot (\lceil {\rm erfi(erfc}(0)) \rceil + \lfloor {\rm erfi(erfi(erfc}(0))) \rfloor - \lceil {\rm erfi(erfc}(0)) \rceil)=24, w(z)为复误差函数, {\rm erfc}(x)为互补误差函数$

$\lceil\exp\left(\lfloor{\rm Im}\left( {\rm Ei} \left( \sqrt{-J_0(0)} \right) \right)\rfloor\right)\rceil \cdot (L_0+E_0)=24, J_\alpha(x)为第一类Bessel函数, L_n为Lucas数, E_n为Euler数$

$\lceil{\rm Re}(\mathbf {H}_{\mathbf {L}_0(\psi({\rm Hi}(0))} (\zeta(0)))\rceil\cdot \lfloor{\rm Im(Li}(\zeta(0)))\rfloor=24, \mathbf{H}_\alpha(x)为Struve函数, {\rm Li}(x)为对数积分$

$L(L(0,0), \lfloor\lceil {\rm Gi}(0)\rceil/{\rm Gi}(0)\rfloor)=24, L(n, k)为Lah数$

$s(s(0,0), \lceil\lceil {\rm Gi}(0)\rceil/ {\rm Gi}(0)\rceil)=24, s(n,k)为第一类Stirling数$

$\lfloor-\zeta({-\rm Kei}(0))\rfloor\cdot \lfloor Β({\rm Kei(0)+Ber(0), Kei(0)})\rfloor=24, {\rm Kei}(x)为Kelvin\ Kei函数, {\rm B}(p,q)为Euler第二类积分$

$\lceil I_0(\lceil{\rm- Im}(K_0(-{\rm erfc}(0)))\rceil+{\rm erf}({\rm erfc}(0)))\rceil=24, I_\alpha(x)为第一类修正Bessel函数, K_\alpha(x)为第二类修正Bessel函数$

$\left\{{\begin{matrix}\lceil-\frac{\rm erfc(0)}{\rm Gi(0)}\rceil\\{\rm \lfloor -Im(Ker(Kei(0)))\rfloor}\end{matrix}}\right\}-{\rm Ber}(0)=24, {\rm Ker}(x)为Kelvin\ Ker函数, {\displaystyle \left\{{\begin{matrix}n\\k\end{matrix}}\right\}\,}为第二类Stirling数$

$\lfloor\exp(-Z(0))\rfloor \cdot \lfloor-{\rm Bei}(\ln(-{\rm Ber}(0)))\rfloor \cdot \Gamma(E(0))+0=24, {\rm Bei}(x)为Kelvin\ Bei函数, Z(x)为Riemman-Siegel\ Z函数$

$Q_{\lfloor{\rm Re}(Q_{{\rm Kei}(0)}(K(0)))\rfloor}(E(0))-\exp(\exp(0))=24, Q_n(z)为第二类Legendre函数$

$\lfloor C_{{\rm Ei}(P_0(0))}(\exp({\rm Ber}(0))\rfloor\cdot \lceil Z(0)\rceil=24, P_n(x)为第一类Legendre函数, C_n(x)为重正规化Gegenbauer多项式$

$\lfloor T_{\exp(0)}(K(0))\rfloor \cdot \lfloor {\rm -Re}(T_{\exp(0)}(Z(0)))\rfloor=24, T_n(x)为第一类Chebyshev多项式$

$\lfloor U_{\exp(\exp(0))}(K(0))\rfloor + \lceil U_{\rm erfc(0)}(\exp(\exp(0)))\rceil=24, U_n(x)为第二类Chebyshev多项式$

$\lfloor{\rm Im}(\rho_{\rm Ber(0)})\rfloor+\lceil j_{\rm Ber(0), \exp(\exp(0))}\rceil+0=24, \rho_k为Riemann\ \zeta函数的零点函数, j_{n,k}为J_n(x)的零点函数$

$\lceil P_{\lceil cFh(E(0)\rceil}^{(\lceil FsG(\zeta(0))\rceil,\exp(0))}(\lfloor -\zeta({\rm Bi}(0)))\rceil=24, P_n^{(\alpha,\beta)}(z)为Jacobi多项式, FsG(z)为Fresnel\ G函数$

$\lceil\exp({\rm Im(\ln(-(0)_0)))}\rceil+0+0=24, (a)_n为递进阶乘的Pochhammer符号$

$\lfloor H_{\frac{\rm erfc(0)}{\rm Ai(0)}}(E(0))\rfloor \cdot \lceil -Z(0)\rceil=24, H_n(x)为Hermite多项式$

$\lceil L_{\exp(\exp(0))}(\theta(\xi(0)))\rceil\cdot \lceil -\theta(-Z(0))\cdot K(0)\rceil =24, L_n(x)为Laguerre多项式, \theta(t)为Riemann–Siegel\ \theta函数$

$\lceil R_{\lceil\arg(-\exp(0))\rceil}^0(K(0))\rceil+\exp(0)=24, R_n^m(r)为Zernike多项式$

$\lceil -{\rm Re(\theta_c(\arg(-\exp(0))|\exp(\exp(0))))\rceil-\lfloor \rm Im(\theta_c(\arg(-\exp(0))|\exp(\exp(0))))\rfloor=24}, \theta_c(z|m)为Neville \ \theta \ c函数$

$-U(-\lfloor \arg(-D(0))\rfloor,-\lfloor \arg(-D(0))\rfloor,-\lfloor \arg(-D(0))\rfloor)\cdot \exp(\eta(D(0)))=24, U(a,b,z)为Tricomi函数, D(x)为Dirichlet函数$

$R(\beta(0))\lfloor\beta(-\exp(\exp(0))\cdot\exp(\exp(0)))\rfloor^{\beta(0)}=24, \beta(s)为Dirichlet\ \beta函数, R(x)为Riemann函数$

因为很多特殊函数当自变量为0时值相等（如 $-\zeta(0)= \xi(0)= \eta(0)=\beta(0)=\frac{1}{2}$ 、 $E(0)= K(0)= \Pi(0|0)=-{\rm si}(0)=\arccos(0)={\rm arccot}(0)=\frac{\pi}{2}$ 、 ${\rm erfc}(0)=w(0)=B_0=C_0=E_0=\cos0=\sec0=A(0,0)=\exp(0)=J_0(0)=0!=1$ 等），所以用上面的很多函数还能组合出很多个满足条件的式子